Important Quantitative Aptitude Quiz for Competitive Exam
Topic: Time & Work Important Quiz
Solution of All Questions is Given below
1 >>Q1. Deepa and Poonam can do a piece of work in 8 days. Deepa alone can do the work in 10 days. In how many days, can Poonam finish the work alone? ? (A) 40 days
 (B) 45 days
 (C) 50 days
 (D) 35 days
 (A) 3.33 days
 (B) 3.75 days
 (C) 3.66 days
 (D) 3.25 days
 (A) 8
 (B) 6
 (C) 3
 (D) 4
 (A) 17
 (B) 15
 (C) 16
 (D) 18
5 >>Q11. P and Q can do a piece of work in 15 days, Q and R can do the work in 20 days. P and R can do the work in 12 days. In how many days can P finish the work? ?
 (A) 18
 (B) 20
 (C) 17
 (D) 22
 (A) 10
 (B) 12
 (C) 8
 (D) 4
7 >>Q13. 5 men can do a piece of work in 10 days and 6 women can do the same work in 15 days. In how many days can 2 men and 3 women together do the work? ?
 (A) 12.818
 (B) 13.182
 (C) 13.637
 (D) 12.454
 (A) 32
 (B) 22.5
 (C) 28
 (D) 12.5
 (A) 24
 (B) 21
 (C) 23
 (D) 22
 (A) 40 days
 (B) 54 days
 (C) 50 days
 (D) 45 days
Quantitative Aptitude Quiz
11 >>Q17. A sum of money is sufficient to pay A's wage for 16 days or B's wage for 12 days. For how many days is the sum sufficient to pay the wages for both A and B? ? (A) 5.71428571428571
 (B) 6.71428571428571
 (C) 5.85714285714286
 (D) 6.85714285714286
12 >>Q18. A and B can complete a piece of work in 12 and 15 days respectively. They began to work together, but A left the work after 4 days due to illness. In how many days B alone will finish the remaining work? ?
 (A) 6 days
 (B) 7 days
 (C) 8 days
 (D) 9 days
 (A) 5
 (B) 4
 (C) 3
 (D) 2
 (A) 56
 (B) 44
 (C) 52
 (D) 48
 (A) 25
 (B) 24
 (C) 22
 (D) 23
Topic: Progression Important Quiz
1 >>Q3. The sum of the 3rd term and the 60th term of an P. is 60. If it has 62 terms. What will be the sum of all its terms? ?
 (A) 1922
 (B) 1891
 (C) 1829
 (D) 1860
 (A) Does not exist
 (B) 1
 (C) 0
 (D) 1
3 >>Q5. The sum of first twenty terms of an arithmetic progression is 210. What will be the sum of its 10th and 11th term? ?
 (A) 56
 (B) 28
 (C) 21
 (D) 42
 (A) 5643
 (B) 5640
 (C) 2928
 (D) 5673
 (A) 20, 20/7, 180/14, ....
 (B) 40, 80/3, 160/9, ...
 (C) 8, 16/3, 32/9, ...
 (D) None of these
 (A) 4
 (B) 6
 (C) 12
 (D) 3
 (A) 18
 (B) 16
 (C) 14
 (D) 12
 (A) 23/50
 (B) 23
 (C) 50
 (D) 50/23
 (A) 883
 (B) 887
 (C) 885
 (D) 889
 (A) 99:89
 (B) 99:83
 (C) 99:80
 (D) 99:86
11 >>Q19. Ankit and Ashok start saving money in a certain month of a year. Every month from then on, Ankit increased his savings by an amount equal to the savings of Ashok in the first month and Ashok increased his savings by an equal amount to the savings of Ankit in the first month. In 20 months the total of the amounts saved by both is equal to 2100, what will be the amount saved by Ankit in the second month? ?
 (A) Rs.10.5
 (B) Rs.l4
 (C) Rs.8
 (D) Cannot be determined
 (A) 32
 (B) 18
 (C) 21
 (D) 24
 (A) 35
 (B) 20
 (C) 24
 (D) 30
 (A) 12th
 (B) 8th
 (C) 10th
 (D) 11th
 (A) 864 cm²
 (B) 512 cm²
 (C) 1024 cm²
 (D) None of these
 (A) 5
 (B) 4
 (C) 3
 (D) 2
Topic: Pipe & Cistern Important Quiz
 (A) 33
 (B) 30
 (C) 28
 (D) 35
 (A) 114 litres
 (B) 110 litres
 (C) 108 litres
 (D) 105 litres
 (A) 120 min
 (B) 150 min
 (C) 200 min
 (D) 170 min
 (A) 24 hours
 (B) 15 hours
 (C) 18 hours
 (D) 12 hours
 (A) 540 litres
 (B) 480 litres
 (C) 270 litres
 (D) 350 litres
 (A) 7
 (B) 8
 (C) 6
 (D) 9
 (A) 15
 (B) 14
 (C) 17
 (D) 16
 (A) 18 minutes
 (B) 16 minutes
 (C) 17 minutes
 (D) 15 minutes
 (A) 25
 (B) 26
 (C) 24
 (D) 27
 (A) 24 hours
 (B) 21 hours
 (C) 18 hours
 (D) 10 hours
 (A) 15 hours
 (B) 16 hours
 (C) 12 hours
 (D) 11 hours
12 >>Q15. Two taps can fill a cistern in 2 and 4 hours respectively. How much time after opening the both taps, second tap should be turned off so that the cistern be filled in 1 hour? ?
 (A) 1/3 hours
 (B) 1 hour
 (C) 2/3 hours
 (D) 2 hours
 (A) 7 3/7 min.
 (B) 2 3/7 min.
 (C) 3 3/7 min.
 (D) 6 3/7 min.
 (A) 1/7 min.
 (B) 1/3 min.
 (C) 1/2 min.
 (D) 1 min.
 (A) 157 min.
 (B) 167 min.
 (C) 165 min.
 (D) 164 min.
Solution for Important Quantitative Aptitude Quiz
Pipe and Cistern
1

Exp. Let pipe
'B' fill X parts of a tank in a minute.

2

Exp. In 15
minutes, amount of litres filled = 12x15 + 6x15 = 270 litres.

3

Exp. Pipe 'A'
fills 1/40th of tank in a minute.

4

Exp. Let Pipe
'A' take X hours to fill the tank.

5

Exp. Let pipe
'B' take X minutes to fill the tank.

6

Exp. Let first
pipe be open for X minutes.

7

Exp. Let X(in
hours) be the time taken to fill the tank.

8

Exp. Amount of
tank filled in 4 minutes by both A and B = 4/24 + 4/32 = 7/24.

9

Exp. Let X be
the time taken for the tank to be full.

10

Exp. Let X be
the time taken by pipe Q to fill the tank.

11

Exp. Let X be
the time taken to fill the cistern.

12

Exp. Let X be
the time both taps operate.

13

Exp. Amount
filled in two minutes = 1/6 + 1/7 = 13/42.

14

Exp. Let X be
the time the pipes were blocked.

15

Exp. Amount of
cistern filled in 3 minutes = 1/20 + 1/30  1/15 = 1/60.

Time and Work
1

Exp. Amount of
work done by Deepa in 8 days 0.8Amount
of work done by Poonam in 8 daysTRUETime taken by Poonam to complete the work
alone= 8x5= 40 days(to complete 2/10 x 5 = 1 work).

2

Exp. Number of
days taken by B and C to complete the work together= 1/(1/10 + 1/30) = 7.5
days.A takes 7.5/2 = 3.75 days.

3

Exp. Let number
of cats =(8 cats)x(8 minutes) / 8 mice= A x (16 minutes) / 6 mice.A = 3.

4

Exp. Amount of
work completed by P in 9 daysTRUEWork to be completedTRUENumber of days
required by P and Q to complete rest of the workTRUETotal number of days = 9
+ 7 = 16.

5

Exp. Let time
taken by P, Q and R alone to complete the work = A, B andWe have, (1/A +
1/B)0.066 1/B + 1/C0.051/A + 1/C0.083 Solving the three equations, A = 20.

6

Exp. Let A be
the number of minutes required.(12 rabbits) x (12 minutes) / 12 carrots = (4
rabbits) x A / 4 carrots.A = 12.

7

Exp. Amount of
work completed by one man in one day0.020.02Amount of work completed by one
woman in one day0.01111111111111110.0111111111111111Amount of work done by 2
men and 3 women in one day0.07333333333333330.0733333333333333Number of days
required to complete the job13.636363636363613.6363636363636= 13.637.

8

Exp. Let Q
finish the work in A number of days.Since P is 60% more efficient than Q,
1.6/A = 1/20.A = 32.

9

Exp. Let A be
the number of boxes 12men can load in 1hour (60 minutes).(1man)x(12minutes) /
3 boxes = (12men)x(60minutes) /A = 180, i.e. Number of trucks loaded = 180/8
= 22.5.Number of trucks loaded fully = 22.

10

Exp. Let A, B
and C take X, Y and Z days to finish the work alone.Amount of work completed
by C in a day = 1/Z.Amount of work completed by A and B together in a day =
1/X + 1/Y.We have, 2(1/Z) = (1/X + 1/Y)Number of days taken by A, B and C to
finish the work together= 15days.1/(2/Z + 1/Z) = 15,Z = 45days.

11

Exp. Number of
days the sum will be sufficient topay the wages for both A and
B6.857142857142866.85714285714286= 6 6/7.

12

Exp. Amount of
work completed in 4 days = 4/12 + 4/15 = 3/5.To complete the remaining 2/5th
of the work, B requires (2/5) x 15 = 6 days.

13

Exp. Work done
by A in m days = m/48.Work done by A and B in next m days = m/48 + m/36.Work
done by A, B and C in remaining days = (122m)/48 + (122m)/36 +
(122m)/12.m/48 + m/48 + m/36 + (122m)/48 + (122m)/36 + (122m)/12 = 1.m =
3.

14

Exp. Amount of
provisions = 630 x 24 x 2 = 30240.Let A be number of days the provisions last
in second case.360 x A x 3/2 = 30240.A = 56.

15

Exp. Let number
of boxes loaded be(1man)x(8minutes) / (1box)= (16men)x(70minutes) / (A).A =
140.Number of trucks filled = 140/6 = 23.33.Number of trucks completely
filled = 23.

Progression Solution
1

Exp. Sum of 3rd term
and 60th term

2

Exp. Sum to
infinity exists only for a descending GP.

3

Exp. Sum of
first twenty terms of an P.

4

Exp. Sum of AP =
(n/2)(2a + (n1)d).

5

Exp. Let 'a' be
the first term and 'r' be the common ratio.

6

Exp. Only three
such three digit numbers exist, 124, 139, 248.

7

Exp. Let the
three numbers be ad, a , a+d.

8

Exp. Last term
of AP = a + (n1)d = 55.

9

Exp. Difference
of 9th and 8th terms of a GP

10

Exp. Sum of 30
terms = (30/2)(2x10 + 29x5) = 2475.

11

Exp. Let amount
saved by Ankit in first month =

12

Exp. a = 16.

13

Exp. Numbers
between 450 and 950 are divisible by both 3 and 7 = (950450)/(3x7) = 24.

14

Exp. Sum of GP =
1.1 lakhs.

15

Exp. Area of T2
is half of T1, area of T3 is half of T2.

16

Exp. a(r^4 
1)/(r1) = 120, a/(r1) = 120/(r^4  1).

0 comments:
Post a Comment